document.write( "Question 1085178: A) Equal masses of water at 20 Celsius and iron at 40 Celsius are put together in a Styrofoam cup. The water has a specific heat of 1 cal/g C and the iron has a specific heat of 0.113 cal/g C. What do you think the final temp will be of both the water and the iron in the Styrofoam cup? Show your work.\r
\n" ); document.write( "\n" ); document.write( "B) What would happen if you combined equal masses of liquid water at 10 C with ice at 0 C? What do you think the final temp might be?
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Algebra.Com's Answer #699221 by rothauserc(4718)\"\" \"About 
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A) Let x be the final temperature of the mixture
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\n" ); document.write( "The iron is warmer, so its delta temperature is 40 - x
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\n" ); document.write( "The water's delta temperature is x - 20
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\n" ); document.write( "the energy amount going out of the iron is equal to the energy amount going into the cool water. This means,
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\n" ); document.write( "q(lost) = q(gain)
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\n" ); document.write( "we are given that the mass(m) of the iron is the same as the water
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\n" ); document.write( "we know
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\n" ); document.write( "q = m * delta temperature * specific heat
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\n" ); document.write( "m * (40 - x) * 0.113 = m * (x - 20) * 1
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\n" ); document.write( "now we solve for x
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\n" ); document.write( "4.52 - 0.113x = x - 20
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\n" ); document.write( "-1.113x = -24.52
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\n" ); document.write( "x = 8.1222
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\n" ); document.write( "final temperature is 8.1222 C
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\n" ); document.write( "B) Our balance equation, q(lost) = q(gain) is
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\n" ); document.write( "m * (10 - x) * 1 = m * (x - 0) * 1
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\n" ); document.write( "10 - x = x
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\n" ); document.write( "2x = 10
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\n" ); document.write( "x = 5
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\n" ); document.write( "we expect the final temperature to be 5 C
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