document.write( "Question 1085166: A lecturer wants to select two students at random from a class of 7 males and 3 females. What is the probability the two students chosen are female?\r
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document.write( "Select one:
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document.write( "A. 0.09
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document.write( "B. 0.22
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document.write( "C. 0.3
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document.write( "D. 0.67 \n" );
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Algebra.Com's Answer #699206 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let \n" ); document.write( "A = number of ways to choose 2 females \n" ); document.write( "B = number of ways to choose 2 people (any gender)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Order will not matter. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 3 ways to pick 2 females. Let's consider the group of females {X,Y,Z} where the letters are codenames for their actual names \n" ); document.write( "The three groups we can form are: {X,Y}, {Y,Z}, {X,Z} \n" ); document.write( "Each group in a set of curly braces \n" ); document.write( "Note how order does not matter. Something like {X,Y} is the same as {Y,X}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "An alternative viewpoint is to consider that there are 3 ways to not pick a female. The three cases would be {X}, {Y}, and {Z}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you wish to use a formula, then you can use the nCr combination formula to get \n" ); document.write( "n C r = (n!)/(r!*(n-r)!) \n" ); document.write( "3 C 2 = (3!)/(2!*(3-2)!) \n" ); document.write( "3 C 2 = (3!)/(2!*1!) \n" ); document.write( "3 C 2 = (3*2!)/(2!*1!) \n" ); document.write( "3 C 2 = (3)/(1!) \n" ); document.write( "3 C 2 = (3)/(1) \n" ); document.write( "3 C 2 = 3/1 \n" ); document.write( "3 C 2 = 3 \n" ); document.write( "So that confirms the previous results \n" ); document.write( "In this case, n = 3 because there are three applicants to choose from and r = 2 because that's the number of selections made\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So far, we know that A = 3 because there are three ways to pick two women (from a pool of 3).\r \n" ); document.write( "\n" ); document.write( "---------------------------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using the same formula, but now with n = 10 (there are 10 people total), we get \n" ); document.write( "n C r = (n!)/(r!*(n-r)!) \n" ); document.write( "10 C 2 = (10!)/(2!*(10-2)!) \n" ); document.write( "10 C 2 = (10!)/(2!*8!) \n" ); document.write( "10 C 2 = (10*9*8!)/(2!*8!) \n" ); document.write( "10 C 2 = (10*9)/(2!) \n" ); document.write( "10 C 2 = (10*9)/(2*1) \n" ); document.write( "10 C 2 = 90/2 \n" ); document.write( "10 C 2 = 45\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Indicating that there are 45 different unique groups we can form if we do not worry about the gender of who is selected.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This means that B = 45\r \n" ); document.write( "\n" ); document.write( "---------------------------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now divide the values A and B to get A/B = 3/45 = 1/15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The probability as a fraction is 1/15. Don't forget to fully reduce. This value is exact.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Because your teacher wants the answer in decimal form, you would use a calculator or long division to get 1/15 = 0.06666666666667 which is approximate. That value rounds to 0.067\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Because this answer isn't listed, I'm assuming there's a typo somewhere. A guess I have is that choice D should be 0.067 instead of 0.67\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or perhaps choice D should be 0.07 instead of 0.67\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In any event, I'm thinking your teacher meant to have the answer be choice D. I would check with the teacher though.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------------------------------- \n" ); document.write( "---------------------------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Final Answer: choice D) 0.67 \n" ); document.write( "Note: Look at the section above for an explanation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Edit: MathLover1's solution makes sense on the surface, but looking at it closer there's a flaw in the logic. The answer (3/10)*(3/10) = 9/100 = 0.09 would only apply if the first applicant chosen is put back into the pool. It doesn't make sense to select the same applicant twice. \n" ); document.write( " \n" ); document.write( " |