document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084611>Question 1084611</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of an alloy that is 20% copper should be mixed with 400 ounces of an alloy that is 80% copper in order to get an alloy that is 50% copper? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #699192 by </B><A HREF=/tutors/aboutme.mpl?userid=adamhen894><B>adamhen894(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=adamhen894><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=699192\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x ounces of 20% copper <BR>\n" );
document.write( "mix with <BR>\n" );
document.write( "400 ounces of 80% copper<BR>\n" );
document.write( "to get<BR>\n" );
document.write( "(x+400) ounces of 50% copper\r<BR>\n" );
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document.write( "set up the equation, solve for x <BR>\n" );
document.write( "0.2x+0.8(400)=0.5(x+400)\r<BR>\n" );
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document.write( "x = 400 ounces<BR>\n" );
document.write( "if you input x in the equation, it equals on both side.\r<BR>\n" );
document.write( "\n" );
document.write( "if you have any alternative solution, i would love to hear.<BR>\n" );
document.write( "adamchen894@gmail.com </SPAN>\n" );
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