document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1085153>Question 1085153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the sum of money when compounded annually become 1140 in a 2 years & 1710 in 3 years at the rate of interest<BR>\n" );
document.write( "A 30%<BR>\n" );
document.write( "B 40%<BR>\n" );
document.write( "C 50%<BR>\n" );
document.write( "D 60% </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #699188 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=699188\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in 2 years it is equal to 1140<BR>\n" );
document.write( "in 3 years it is equal to 1710\r<BR>\n" );
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document.write( "between year 2 and year 3, it grew from 1140 to 1710.\r<BR>\n" );
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document.write( "this means that the third year amount is 1.5 * the second year amount, because 1710 / 1140 = 1.5\r<BR>\n" );
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document.write( "the actual growth rate would be (1710 - 1140) / 1140 = .5\r<BR>\n" );
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document.write( "a growth rate of .5 is equal to 50%.\r<BR>\n" );
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document.write( "your solution should be 50%.\r<BR>\n" );
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document.write( "a growth rate of 50% means that the value at each succeeding year is 1.5 times the value of the preceding year.\r<BR>\n" );
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document.write( "to find out what the starting value must have been, divide 1140 by (1.5)^2 to get 506 and 2/3.\r<BR>\n" );
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document.write( "multiply 506 and 2/3 by 1.5^3 and you get 1710.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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