document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1085145>Question 1085145</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that 2 cards are drawn from a standard&#8203; 52-card deck. Find the following probabilities.<BR>\n" );
document.write( "&#8203;a) Assume the cards are drawn without replacement. Find the probability of drawing 2 face card<BR>\n" );
document.write( "s.<BR>\n" );
document.write( "&#8203;b) Assume the cards are drawn with replacement. Find the probability of drawing 2 face card<BR>\n" );
document.write( "s. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #699184 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=699184\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 4x3, or 12 face cards in a deck of 52, so to draw 2 face cards without replacement, we have:<BR>\n" );
document.write( "12/52 x 11/51=0.04562594268476621417797888386124 as the probability<BR>\n" );
document.write( "With replacement, we have:<BR>\n" );
document.write( "12/52²=0.05325443786982248520710059171598 as the probability. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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