document.write( "Question 1085057: Find the radius of a circle with center at (2,3),if a chord of lenght 8 is bisected at (-1,4) with solution Po plz
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Algebra.Com's Answer #699180 by ikleyn(52781)\"\" \"About 
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document.write( "Three segments make a right-angled triangle:\r\n" );
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document.write( "1)  the half of the chord;\r\n" );
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document.write( "2)  the perpendicular bisector from the center of the circle to the chord;  and\r\n" );
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document.write( "3)  the radius drawn from the center to the chord's endpoint.\r\n" );
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document.write( "The half of the chord has the length of \"8%2F2\" = 4 units.\r\n" );
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document.write( "The perpendicular bisector from the center of the circle to the chord has the length\r\n" );
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document.write( "    \"sqrt%28%282-%28-1%29%29%5E2+%2B+%283-4%29%5E2%29\" = \"sqrt%283%5E2+%2B+%28-1%29%5E2%29\" = \"sqrt%2810%29\".\r\n" );
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document.write( "So, the right-angled triangle has two legs of 4 units and \"sqrt%2810%29\" units long.\r\n" );
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document.write( "The radius of the circle is the hypotenuse of this triangle.\r\n" );
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document.write( "Hence, its length is \"sqrt%284%5E2+%2B+%28sqrt%2810%29%29%5E2%29\" = \"sqrt%2816+%2B+10%29\" = \"sqrt%2826%29\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer.  The radius of the circle is  \"sqrt%2826%29\"  units long.\r
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