document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084939>Question 1084939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. For a rollerblading party there are 50 tickets available. Jason buys 6 tickets and Heather buys three times as many as Jason bought. How many tickets are left to be sold?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #699161 by </B><A HREF=/tutors/aboutme.mpl?userid=emathwiz><B>emathwiz(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=emathwiz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=699161\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Let's let Heather's amount of tickets bought be h Jason's be j and the amount remaining be r. Set up the equations like this: <BR>\n" );
document.write( "j=6\r<BR>\n" );
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document.write( "h=3j\r<BR>\n" );
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document.write( "50= j+h+r Jason's value is given so let's fill in the values:\r<BR>\n" );
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document.write( "h=3(6)\r<BR>\n" );
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document.write( "50= 6+18+r<BR>\n" );
document.write( "50= 24+r Subtract 24 to both sides.\r<BR>\n" );
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document.write( "26=r<BR>\n" );
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