document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084891>Question 1084891</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Am ordinary(fair) die is a cube with the numbers 1 thru 6 on the sides ( representEd by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This summer is recorded as the outcome of a single trial of a random experiment.\r<BR>\n" );
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document.write( "Compute the probability of each of the following events:<BR>\n" );
document.write( "Event A: the sum is greater than 7<BR>\n" );
document.write( "Event B: themail sum is an odd number \r<BR>\n" );
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document.write( "Write your answers as exact fractions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #699145 by </B><A HREF=/tutors/aboutme.mpl?userid=emathwiz><B>emathwiz(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=emathwiz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=699145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For this kind of problem the probability is the number of outcomes that work over the total number of outcomes. The total number of outcomes for two rolls is \r<BR>\n" );
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document.write( "6+5+4+3+2+1=21 This works because: <BR>\n" );
document.write( "(first roll, second roll)\r<BR>\n" );
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document.write( "(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)= 6 \r<BR>\n" );
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document.write( "(2,2) (2,3) (2,4) (2,5) (2,6)=5\r<BR>\n" );
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document.write( "(3,3) (3,4) (3,5) (3,6)=4\r<BR>\n" );
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document.write( "(4,4) (4,5) (4,6)=3\r<BR>\n" );
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document.write( "(5,5) (5,6)=2\r<BR>\n" );
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document.write( "(6,6)=1 \r<BR>\n" );
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document.write( "Looking at all these possibilities from here we just count the ones that work.\r<BR>\n" );
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document.write( "9 sums are greater than 7 so the probability for Event A is 9/21 or 3/7\r<BR>\n" );
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document.write( "For Event B there are once again 9 odd sums so the probability is 9/21 or 3/7.\r<BR>\n" );
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document.write( "Keep in mind this is if order doesn't matter! (That's why I don't include 6,3 for example since I wrote 3,6 already) </SPAN>\n" );
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