document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95978>Question 95978</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor completely\r<BR>\n" );
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document.write( "125-27y^3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69906 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69906\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> factor completely\r<BR>\n" );
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document.write( "125 - 27y^3<BR>\n" );
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document.write( "You should recognize this as \"Difference of cubes\" given in most textbooks as:<BR>\n" );
document.write( "  a^3 - b^3  =  (a - b)(a^2 + ab + b^2)<BR>\n" );
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document.write( "In our problem you can see 125 = 5^3 and 27 = 3^3, so we have:<BR>\n" );
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document.write( "   (5 - 3y)(25 + (5*3y) + 9y^2<BR>\n" );
document.write( "which is:<BR>\n" );
document.write( "   (5 - 3y)(25 + 15y + 9y^2)<BR>\n" );
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document.write( "Did this help? </SPAN>\n" );
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