document.write( "Question 1085009: 
I need the answer for question (i) and (ii) both of them please:\r\n" );
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document.write( "(2) Let {an} and {bn} for n = 1,2,3,... .\r\n" );
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document.write( "(i) The sequence {an} satisfies the following relation:\r\n" );
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document.write( "                     \"1%2Fa%5Bn%2B1%5D-1%2Fa%5Bn%5D=2\".\r\n" );
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document.write( "Express the general term an in terms of n when a1 = \"1%2F6\"\r\n" );
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document.write( "(ii) The general term of {bn} is given by\r\n" );
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document.write( "                     \"b%5Bn%5D=sqrt%281%2Bn%5E2%29-n\"\r\n" );
document.write( "                     \r\n" );
document.write( "                     Prove that \"b%5Bn%5D%3E=b%5Bn%2B1%5D\"
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Algebra.Com's Answer #699048 by ikleyn(52786)\"\" \"About 
You can put this solution on YOUR website!
.
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document.write( "You are given the sequence \"a%5Bn%5D\" such that \"1%2Fa%5Bn%2B1%5D\" - \"1%2Fa%5Bn%5D\" = 2 and \"a%5B1%5D\" = \"1%2F6\".\r\n" );
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document.write( "Then consider the sequence \"c%5Bn%5D\" determined as \"c%5Bn%5D\" = \"1%2Fa%5Bn%5D\" for all n = 1, 2, 3, . . . \r\n" );
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document.write( "Then \"c%5B1%5D\" = 6 and \"c%5Bn%2B1%5D\" = \"c%5Bn%5D%2B2\".\r\n" );
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document.write( "It is clear that \"c%5Bn%5D\" is nothing else as an arithmetic progression with the first term 6 and the common difference 2.\r\n" );
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document.write( "So, \"c%5Bn%5D\" = 6 + (n-1)*2 = 4 + 2n.\r\n" );
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document.write( "Then \"a%5Bn%5D\" = \"1%2Fc%5Bn%5D\" = \"1%2F%282n%2B4%29\" for all n = 1, 2, 3, . . . \r\n" );
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