document.write( "Question 1084999: One solution, Solution A, is 70% water and 30% acid. Another solution, Solution B, is 40% water and 60% acid. How many liters of each of these solutions would be required to make 300 liters of a solution which is 60% water and 40% acid? \n" ); document.write( "

Algebra.Com's Answer #699002 by jorel1380(3719) $\"\"$ $\"About$

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Solution B is 60% acid, and solution A is 30% acid. Let b be for solution B, then solution A is (300-b). So:
\n" ); document.write( ".6b+.3(300-b)=300(.4)
\n" ); document.write( ".3b+90=120
\n" ); document.write( "Solve for b.
\n" ); document.write( "☺☺☺☺ \n" ); document.write( "

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