document.write( "Question 1084974: A park has a circular lake 240' in diameter. A walkway 6' wide is around the lake. Determine number of sq. yds. in the walk. \r
\n" ); document.write( "\n" ); document.write( "A = area. \r
\n" ); document.write( "\n" ); document.write( "240' = 80 yds., 6' = 2 yds.\r
\n" ); document.write( "\n" ); document.write( "A = pi(40 + 2)(40 - 2)
\n" ); document.write( "A = pi(42)(38)
\n" ); document.write( "A = pi(1596)
\n" ); document.write( "A = 5013.9936 = 5014 sq. yds. \r
\n" ); document.write( "\n" ); document.write( "Area of circle: pi * r^2 \r
\n" ); document.write( "\n" ); document.write( "Area of lake: pi * 40 * 40 = 5026.56 = 5027 sq. yds. \r
\n" ); document.write( "\n" ); document.write( "Area of lake and walk: pi * 42 * 42 = 5541.7824 = 5542 sq. yds. \r
\n" ); document.write( "\n" ); document.write( "Area of walk: 5542 - 5027 = 515 sq. yds. \r
\n" ); document.write( "\n" ); document.write( "Where am I incorrect. Non-homework. Thanks.
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Algebra.Com's Answer #698992 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
A park has a circular lake \"240\"' in diameter.->
\n" ); document.write( "\"240in+=+6.67yd\"\r
\n" ); document.write( "\n" ); document.write( " then, radius is \"6.67yd%2F2=3.33yd\"\r
\n" ); document.write( "\n" ); document.write( "area of the lake is \r
\n" ); document.write( "\n" ); document.write( "\"%283.33yd%29%5E2%2Api=11.1%2Api%2Ayd%5E2\"\r
\n" ); document.write( "\n" ); document.write( " A walkway \"6in\"wide is around the lake;\r
\n" ); document.write( "\n" ); document.write( "\"6in+=+0.17yd\"\r
\n" ); document.write( "\n" ); document.write( " so, radius of the lake and walkway is \"3.33yd%2B0.17yd=3.5yd\"\r
\n" ); document.write( "\n" ); document.write( " area of the lake and walkway:
\n" ); document.write( "\"%283.5yd%29%5E2%2Api=12.25%2Api%2Ayd%5E2\"\r
\n" ); document.write( "\n" ); document.write( " area of the walkway alone is:
\n" ); document.write( " \"12.25%2Api%2Ayd%5E2-11.1%2Api%2Ayd%5E2=1.15%2Api%2Ayd%5E2=1.15%2A3.14%2Ayd%5E2=3.611yd%5E2\"\r
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