document.write( "Question 1084974: A park has a circular lake 240' in diameter. A walkway 6' wide is around the lake. Determine number of sq. yds. in the walk. \r
\n" ); document.write( "\n" ); document.write( "A = area. \r
\n" ); document.write( "\n" ); document.write( "240' = 80 yds., 6' = 2 yds.\r
\n" ); document.write( "\n" ); document.write( "A = pi(40 + 2)(40 - 2)
\n" ); document.write( "A = pi(42)(38)
\n" ); document.write( "A = pi(1596)
\n" ); document.write( "A = 5013.9936 = 5014 sq. yds. \r
\n" ); document.write( "\n" ); document.write( "Area of circle: pi * r^2 \r
\n" ); document.write( "\n" ); document.write( "Area of lake: pi * 40 * 40 = 5026.56 = 5027 sq. yds. \r
\n" ); document.write( "\n" ); document.write( "Area of lake and walk: pi * 42 * 42 = 5541.7824 = 5542 sq. yds. \r
\n" ); document.write( "\n" ); document.write( "Area of walk: 5542 - 5027 = 515 sq. yds. \r
\n" ); document.write( "\n" ); document.write( "Where am I incorrect. Non-homework. Thanks.
\n" ); document.write( "

Algebra.Com's Answer #698986 by Fombitz(32388)\"\" \"About 
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\"A%5Bwalk%5D=%28pi%2F4%29%28%28240%2B12%29%5E2-240%5E2%29\"
\n" ); document.write( "\"A%5Bwalk%5D=%28pi%2F4%29%28252%5E2-240%5E2%29\"
\n" ); document.write( "\"A%5Bwalk%5D=%28pi%2F4%29%285904%29\"
\n" ); document.write( "\"A%5Bwalk%5D=1476pi\" \"ft%5E2\"
\n" ); document.write( "\"A%5Bwalk%5D=%281476pi%29%2F9\"
\n" ); document.write( "\"A%5Bwalk%5D=164pi\"\"yd%5E2\"\r
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