document.write( "Question 1084770: Triangle ABC has vertices A(-2, -3), B(2, 5), and C(6, -7). Find the circumcentre and the centroid. \n" ); document.write( "
Algebra.Com's Answer #698962 by Edwin McCravy(20059)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let the equation of the circle be\r\n" );
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document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"\r\n" );
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document.write( "Substituting each of the points, we have this system\r\n" );
document.write( "of three equations:\r\n" );
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document.write( "Subtracting the first two equations\r\n" );
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document.write( "\"%28-2-h%29%5E2%2B%28-3-k%29%5E2-%282-h%29%5E2-%285-k%29%5E2=0\"\r\n" );
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document.write( "\"%28-2-h%29%5E2-%282-h%29%5E2\"\"%22%22=%22%22\"\"%285-k%29%5E2-%28-3-k%29%5E2\"\r\n" );
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document.write( "Factoring both sides as the difference of squares:\r\n" );
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document.write( "\"%28%28-2-h%29%5E%22%22-%282-h%29%29%28%28-2-h%29%5E%22%22%2B%282-h%29%29\"\"%22%22=%22%22\"\"%28%285-k%29%5E%22%22-%28-3-k%29%29%28%285-k%29%5E%22%22%2B%28-3-k%29%29\"\r\n" );
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document.write( "\"%28-2-h-2%2Bh%29%28-2-h%2B2-h%29\"\"%22%22=%22%22\"\"%285-k%2B3%2Bk%29%285-k-3-k%29\"\r\n" );
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document.write( "\"8h\"\"%22%22=%22%22\"\"%288%29%282-2k%29\"\r\n" );
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document.write( "Divide both sides by 8\r\n" );
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document.write( "\"h\"\"%22%22=%22%22\"\"2-2k\"  <--equation A \r\n" );
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document.write( "Subtracting the second and third equations\r\n" );
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document.write( "\"%282-h%29%5E2%2B%285-k%29%5E2-%286-h%29%5E2-%28-7-k%29%5E2=0\"\r\n" );
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document.write( "\"%282-h%29%5E2-%286-h%29%5E2\"\"%22%22=%22%22\"\"%28-7-k%29%5E2-%285-k%29%5E2\"\r\n" );
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document.write( "Factoring both sides as the difference of squares:\r\n" );
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document.write( "\"%28%282-h%29%5E%22%22-%286-h%29%29%28%282-h%29%5E%22%22%2B%286-h%29%29\"\"%22%22=%22%22\"\"%28%28-7-k%29%5E%22%22-%285-k%29%29%28%28-7-k%29%5E%22%22%2B%285-k%29%29\"\r\n" );
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document.write( "\"%282-h-6%2Bh%29%282-h%2B6-h%29\"\"%22%22=%22%22\"\"%28-7-k-5%2Bk%29%28-7-k%2B5-k%29\"\r\n" );
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document.write( "\"%28-4%29%288-2h%29\"\"%22%22=%22%22\"\"%28-12%29%28-2-2k%29\"\r\n" );
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document.write( "Divide both sides by -4\r\n" );
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document.write( "\"8-2h\"\"%22%22=%22%22\"\"3%28-2-2k%29\"\r\n" );
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document.write( "\"8-2h\"\"%22%22=%22%22\"\"-6-6k%29\"\r\n" );
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document.write( "Divide both sides by 2\r\n" );
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document.write( "\"4-h\"\"%22%22=%22%22\"\"-3-3k%29\"\r\n" );
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document.write( "\"-h\"\"%22%22=%22%22\"\"-7-3k%29\"\r\n" );
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document.write( "\"h\"\"%22%22=%22%22\"\"7%2B3k%29\"  <--equation B\r\n" );
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document.write( "---------------------------------\r\n" );
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document.write( "Setting the expressions for h equal in equations A and B:\r\n" );
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document.write( "\"2-2k\"\"%22%22=%22%22\"\"7%2B3k\"\r\n" );
document.write( "\"-5k\"\"%22%22=%22%22\"\"5\"\r\n" );
document.write( "\"k\"\"%22%22=%22%22\"\"-1\"\r\n" );
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document.write( "Substituting in equation B\r\n" );
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document.write( "\"h\"\"%22%22=%22%22\"\"7%2B3%28-1%29%29\"\r\n" );
document.write( "\"h\"\"%22%22=%22%22\"\"7-3%29\"\r\n" );
document.write( "\"h\"\"%22%22=%22%22\"\"4\"\r\n" );
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document.write( "So the circumcenter is (h,k) = (4,-1)\r\n" );
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document.write( "The centroid is the point where the three medians intersect.\r\n" );
document.write( "So we will find the equations of two medians and then solve \r\n" );
document.write( "the system of equations to find their point of intersection\r\n" );
document.write( "which will be the centroid.\r\n" );
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document.write( "First we find the midpoint of AB\r\n" );
document.write( " \r\n" );
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document.write( " <--midpoint of AB\r\n" );
document.write( "We will label that midpoint D\r\n" );
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document.write( "Next we draw the median CD from the vertex C(6,-7)\r\n" );
document.write( "to the midpoint D(0,1) of the opposite side AB:\r\n" );
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document.write( "Next we find the equation of that line. \r\n" );
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document.write( "So we find the slope (gradient) of median CD\r\n" );
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document.write( "\"matrix%281%2C3%2C%0D%0ASlope%2C%22%22=%22%22%2C%281-%28-7%29%29%2F%280-6%29%29%29%29\"\r\n" );
document.write( "\"matrix%281%2C3%2C%0D%0ASlope%2C%22%22=%22%22%2C%281%2B7%29%2F%28-6%29%29%29%29\"\r\n" );
document.write( "\"matrix%281%2C3%2C%0D%0ASlope%2C%22%22=%22%22%2C8%2F%28-6%29%29%29%29\"\r\n" );
document.write( "\"matrix%281%2C3%2C%0D%0ASlope%2C%22%22=%22%22%2C-4%2F3%29%29%29\"  <-- slope of CD\r\n" );
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document.write( "Then we use the point-slope formula:\r\n" );
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document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\"\r\n" );
document.write( "\"y-%28-7%29=expr%28-4%2F3%29%28x-6%29%0D%0A%7B%7B%7By%2B7=expr%28-4%2F3%29x%2B8\"\r\n" );
document.write( "\"y=expr%28-4%2F3%29x%2B1\"  <-- equation of CD \r\n" );
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document.write( "---------------------\r\n" );
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document.write( "Now we find the equation of one of the other two medians,\r\n" );
document.write( "say the median from A to BC \r\n" );
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document.write( "We find the midpoint of BC\r\n" );
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document.write( " <--midpoint of BC\r\n" );
document.write( "We will label that midpoint E(4,-1).\r\n" );
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document.write( "[Notice that E(4,-1) just happens to be the circumcenter, the center\r\n" );
document.write( "of the circle in the first part, which means that BC was a diameter\r\n" );
document.write( "of the circumscribing circle in the first part.  But that is \r\n" );
document.write( "irrelevant to this part, just interesting.]\r\n" );
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document.write( "So we draw the median AE from the vertex A(-2,-3)\r\n" );
document.write( "to the midpoint E(4,-1) of the opposite side AB:\r\n" );
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document.write( "Next we find the equation of the median AE. \r\n" );
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document.write( "So we find the slope (gradient) of median AE\r\n" );
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document.write( "\"matrix%281%2C3%2C%0D%0ASlope%2C%22%22=%22%22%2C%28-1%2B3%29%2F%284%2B2%29%29%29%29\"\r\n" );
document.write( "\"matrix%281%2C3%2C%0D%0ASlope%2C%22%22=%22%22%2C2%2F6%29%29%29\"\r\n" );
document.write( "\"matrix%281%2C3%2C%0D%0ASlope%2C%22%22=%22%22%2C1%2F3%29%29%29\"  <-- slope of median AE\r\n" );
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document.write( "Then we use the point-slope formula:\r\n" );
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document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\"\r\n" );
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document.write( "\"y%2B3=expr%281%2F3%29x%2B2%2F3\"\r\n" );
document.write( "\"y=expr%281%2F3%29x%2B2%2F3-3\"\r\n" );
document.write( "\"y=expr%281%2F3%29x%2B2%2F3-9%2F3\"\r\n" );
document.write( "\"y=expr%281%2F3%29x-7%2F3\"  <-- equation of AE \r\n" );
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document.write( "To find the centroid we solve this system of\r\n" );
document.write( "equations to find the point where those two\r\n" );
document.write( "medians intersect:\r\n" );
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document.write( "\"system%28y=expr%28-4%2F3%29x%2B1%2Cy=expr%281%2F3%29x-7%2F3%29\"\r\n" );
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document.write( "We set the two expressions for y equal:\r\n" );
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document.write( "\"expr%28-4%2F3%29x%2B1=expr%281%2F3%29x-7%2F3\"\r\n" );
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document.write( "Multiply through by 3\r\n" );
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document.write( "\"-4x%2B3=x-7\"\r\n" );
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document.write( "\"-5x=-10\"\r\n" );
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document.write( "\"x=2\"\r\n" );
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document.write( "Substitute in\r\n" );
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document.write( "\"y=expr%28-4%2F3%29x%2B1\"\r\n" );
document.write( "\"y=expr%28-4%2F3%29%282%29%2B1\"\r\n" );
document.write( "\"y=-8%2F3%2B1\"\r\n" );
document.write( "\"y=-8%2F3%2B3%2F3\"\r\n" );
document.write( "\"y=-5%2F3\"\r\n" );
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document.write( "So the centroid (the point where the two (green)\r\n" );
document.write( "medians intersect is \"%28matrix%281%2C3%2C2%2C%22%2C%22%2C-5%2F3%29%29\" \r\n" );
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document.write( "Edwin
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