document.write( "Question 95953: Solve the system\r
\n" ); document.write( "\n" ); document.write( "xy+7=-x
\n" ); document.write( "x^2y=12 \n" ); document.write( "
Algebra.Com's Answer #69894 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
xy+7=-x
\n" ); document.write( "subtract 7 from both sides. xy=-x-7
\n" ); document.write( "divide x into both sides. y=(-x-7)/x
\n" ); document.write( "x^2y=12
\n" ); document.write( "replace y with ((-x-7)/x)
\n" ); document.write( "\"x%5E2%28%28-x-7%29%2Fx%29=12\"
\n" ); document.write( "cancel the x in the denominator with x^2.
\n" ); document.write( "x(-x-7)=12
\n" ); document.write( "-x^2-7x=12
\n" ); document.write( "subtract 12 from both sides. -x^2-7x-12=0
\n" ); document.write( "multiply -1 times both sides. x^2+7x+12=0
\n" ); document.write( "Factor. (x+3)(x+4)=0
\n" ); document.write( "x=-3 and x=-4
\n" ); document.write( "xy+7=-x
\n" ); document.write( "Substitute -3 for x. -3y+7=3
\n" ); document.write( "-3y=3-7=-4
\n" ); document.write( "y=4/3
\n" ); document.write( "1st solution set (-3,4/3)
\n" ); document.write( "check: x^2y=12
\n" ); document.write( "substitute -3 for x and 4/3 for y. 9*4/3=12
\n" ); document.write( "Substitute -4 for x. -4y+7=4
\n" ); document.write( "-4y=4-7=-3
\n" ); document.write( "y=3/4
\n" ); document.write( "2nd solution set (-4,3/4)
\n" ); document.write( "check: x^2y=12
\n" ); document.write( "substitute -4 for x and 3/4 for y. 16*3/4=12
\n" ); document.write( "Phew! Some are tougher than others.
\n" ); document.write( "EdJones\r
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