document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084879>Question 1084879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Betty and Karen have been hired to paint the house in the new development.  Working together the women can paint a house in two-thirds the time it takes Karen working alone.  Betty takes 12 hours to paint a house alone.  How long does it take Karen to paint a house working alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698931 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698931\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let b be Betty, and k be Karen, and n be the time it takes Karen to complete the job. Then:<BR>\n" );
document.write( "1/k=1/n<BR>\n" );
document.write( "So:<BR>\n" );
document.write( "1/b+1/k=1/((2n)/3)<BR>\n" );
document.write( "1/12+1/n=3/2n<BR>\n" );
document.write( "n+12=18<BR>\n" );
document.write( "n=6<BR>\n" );
document.write( "n=6, so k=6, then it takes Karen 6 hours to paint the house alone. Working together, they finish the house in 4 hours. &#9786;&#9786;&#9786;&#9786;<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );