document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084878>Question 1084878</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Stan and Hilda can mow the lawn in 60 minutes if they work together. If Hilda works twice as fast as Stan, how long does it take Stan to mow the lawn alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698929 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hilda takes x minutes, Stan takes 2x minutes<BR>\n" );
document.write( "in 1 minute, Hilda does 1/x and Stan does 1/2x<BR>\n" );
document.write( "that sum=60 minutes<BR>\n" );
document.write( "so 1/x+1/2x=1/60, the proportion that is done by both in 1 minute<BR>\n" );
document.write( "multiply everything by 60x<BR>\n" );
document.write( "60+30=x<BR>\n" );
document.write( "x=90 minutes for Hilda, and 2x=180 minutes for Stan<BR>\n" );
document.write( "in 60 minutes, Hilda does 2/3 and Stand does 1/3, sum is 1.<BR>\n" );
document.write( " </SPAN>\n" );
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