document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95940>Question 95940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/2x - 1/6y = 3<BR>\n" );
document.write( "2/5x + 1/2y = 2\r<BR>\n" );
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document.write( "These are to be solved using the elimination method.  I do not even know where to begin!  Help please!<BR>\n" );
document.write( "Thank You<BR>\n" );
document.write( "Nancy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69887 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to eliminate a variable, you need to get the absolute values of two terms in two different equations to equal each other\r<BR>\n" );
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document.write( "multiplying the first equation by 3 gives (3/2)x-(1/2)y=9\r<BR>\n" );
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document.write( "adding this to the second equation eliminates the y term and gives (19/10)x=11 ... x=110/19\r<BR>\n" );
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document.write( "(2/5)(110/19)+(1/2)y=2 ... (1/2)y=-6/19 ... y=-12/19 </SPAN>\n" );
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