document.write( "Question 1084820: Plz answer it's for my holidays homework.
\n" ); document.write( "The sum of the digits of a two digit number is 15. If 9 is added to the number the digits are interchange. Find the numbers.
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Algebra.Com's Answer #698867 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The sum of the digits of a two digit number is 15. If 9 is added to the number the digits are interchange.\r
\n" ); document.write( "\n" ); document.write( "Suppose the digits are \"x\" and \"y\", so the number is \"10x+%2B+y\"\r
\n" ); document.write( "\n" ); document.write( "if the sum of the digits of a two digit number is \"15\", we have\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=15\"....solve for \"x\"
\n" ); document.write( "\"x=15-y\"..........eq.1\r
\n" ); document.write( "\n" ); document.write( " If \"9\" is added to the number the digits are interchange:\r
\n" ); document.write( "\n" ); document.write( " \"10x+%2B+y%2B9=10y+%2B+x\"\r
\n" ); document.write( "\n" ); document.write( " \"10x+%2B+y%2B9-10y+-+x=0\"\r
\n" ); document.write( "\n" ); document.write( " \"9x+-9y+=-9\"
\n" ); document.write( " \"x+-y+=-1\"....solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( " \"x++=y-1\".........eq.2\r
\n" ); document.write( "\n" ); document.write( "from eq.1 and eq2 we have\r
\n" ); document.write( "\n" ); document.write( "\"15-y+=y-1\"\r
\n" ); document.write( "\n" ); document.write( "\"15%2B1+=y%2By\"\r
\n" ); document.write( "\n" ); document.write( "\"16+=2y\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y=8%29\" -> \"x++=8-1\"->\"highlight%28x=7%29\"\r
\n" ); document.write( "\n" ); document.write( " so the number is \"10x+%2B+y=10%2A7%2B8=highlight%2878%29\"\r
\n" ); document.write( "\n" ); document.write( "check: If \"9\" is added to the number the digits are interchange:\r
\n" ); document.write( "\n" ); document.write( "\"78%2B9=87\" so, the digits are interchange\r
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