document.write( "Question 95946: Lynn invests 10,000$. in one account, he earns 6% interest, in the other, he earns 4.5%. How much did he invest in each account if he makes 570$ in one year?\r
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document.write( "PLEASE HELP!!!!!!!!!!! \n" );
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Algebra.Com's Answer #69886 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .06X+.045(10000-X)=570 \n" ); document.write( ".06X+450-.045X=570 \n" ); document.write( ".015X=570-450 \n" ); document.write( ".015X=120 \n" ); document.write( "X=120/.015 \n" ); document.write( "X=8000 INVESTED @ 6% \n" ); document.write( "10000-8000=2000 INVESTED @4.5% \n" ); document.write( "PROOF \n" ); document.write( "8000*.06+2000*.045=570 \n" ); document.write( "480+90=570 \n" ); document.write( "570=570 \n" ); document.write( " \n" ); document.write( " |