document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95921>Question 95921</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395585368/algebrahomeworkh>Algebra and Trigonometry Structure and Method book 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A woman drove part of a 185 mi trip at 50 mi/h and the rest at 55 mi/h. Find the distance she traveled at 50 mi/h if her total driving time was 3 h and 30 min. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69882 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 55X+50(3.5-X)=185<BR>\n" );
document.write( "55X+175-50X=185<BR>\n" );
document.write( "5X=185-175<BR>\n" );
document.write( "5X=10<BR>\n" );
document.write( "X=10/5<BR>\n" );
document.write( "X=2 HOURS SHE DROVE @ 55 MPH.<BR>\n" );
document.write( "3.5-2=1.5 HOURS SHE DROVE @ 50MPH.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "55*2+50*1.5=185<BR>\n" );
document.write( "110+75=185<BR>\n" );
document.write( "185=185 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );