document.write( "Question 1084755: how many quarts of pure antifreeze must be added to 40 quarts of a 25% antifreeze solution in order to obtain a 60% antifreeze solution (round to the nearest tenth as needed) \n" ); document.write( "
Algebra.Com's Answer #698818 by josgarithmetic(39632)\"\" \"About 
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x, volume of 100% antifreeze to add\r
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\n" ); document.write( "\n" ); document.write( "\"amountAntifreeze%2A100%2FtotalVolume=percentMixture\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28100x%2B25%2A40%29%2F%28x%2B40%29=60\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2810x%2B100%29%2F%28x%2B40%29=6\"\r
\n" ); document.write( "\n" ); document.write( "\"10x%2B100=6x%2B240\"\r
\n" ); document.write( "\n" ); document.write( "\"4x%2B100=240\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B25=60\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=35%29\"------\"quarts\"
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