document.write( "Question 95923This question is from textbook Algebra and Trigonometry Structure and Method book 2
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document.write( ": A man invested $6000, part of it at 5% simple interest and the rest at 7% simple interest. If his annual interest income is $372, how much did he invest at each rate? \n" );
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Algebra.Com's Answer #69881 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .07X+.05(6000-X)=372 \n" ); document.write( ".07X+300-.05X=372 \n" ); document.write( ".02X=372-300 \n" ); document.write( ".02X=72 \n" ); document.write( "X=72/.02 \n" ); document.write( "X=3600 INVESTED @ 7% \n" ); document.write( "6000-3600=2400 INVESTED @ 5%. \n" ); document.write( "PROOF \n" ); document.write( ".07*3600+.05*2400=372 \n" ); document.write( "252+120=372 \n" ); document.write( "372=372 \n" ); document.write( " |