document.write( "Question 95923This question is from textbook Algebra and Trigonometry Structure and Method book 2
\n" ); document.write( ": A man invested $6000, part of it at 5% simple interest and the rest at 7% simple interest. If his annual interest income is $372, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #69881 by checkley71(8403)\"\" \"About 
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.07X+.05(6000-X)=372
\n" ); document.write( ".07X+300-.05X=372
\n" ); document.write( ".02X=372-300
\n" ); document.write( ".02X=72
\n" ); document.write( "X=72/.02
\n" ); document.write( "X=3600 INVESTED @ 7%
\n" ); document.write( "6000-3600=2400 INVESTED @ 5%.
\n" ); document.write( "PROOF
\n" ); document.write( ".07*3600+.05*2400=372
\n" ); document.write( "252+120=372
\n" ); document.write( "372=372
\n" ); document.write( "
\n" );