document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084669>Question 1084669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An electrical company supplies electricity to residential customers for a monthly customer charge of &#8203;$6.64 plus 6.048 cents per&#8203; kilowatt-hour for up to 400&#8203; kilowatt-hours.\r<BR>\n" );
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document.write( "&#8203;(a) Write a linear equation that relates the monthly charge&#8203; C, in&#8203; dollars, to the number x of&#8203; kilowatt-hours used in a&#8203; month, 0 less than or equals x less than or equals 0&#8804;x&#8804;400.\r<BR>\n" );
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document.write( "C=\r<BR>\n" );
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document.write( "&#8203;(Use integers or decimals for any numbers in the expression.  Do not include the&#8203; $ symbol in your&#8203; answer.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698806 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the cost per kilowatt-hour is 6.048 cents, the equation for electric cost would be:<BR>\n" );
document.write( "C=$6.64+$0.06048x <BR>\n" );
document.write( "where C is the monthly cost and x is electric usage in kilowatt-hours, where 0&#8804;x&#8804;400. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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