document.write( "Question 1084672: Find the measure of an angle, if six times its complement is 12° less than it's supplement \n" ); document.write( "
Algebra.Com's Answer #698759 by MathLover1(20850)\"\" \"About 
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Two angles are complementary when they add up to \"90\" degrees.
\n" ); document.write( "Two angles are supplementary when they add up to \"180\" degrees.\r
\n" ); document.write( "\n" ); document.write( "\"alpha%2Bbeta=90\"........1)-> complement of \"alpha\" is \"90-alpha\"
\n" ); document.write( "\"alpha%2Bbeta=180\"........2)->supplement of \"alpha\" is \"180-alpha\"\r
\n" ); document.write( "\n" ); document.write( "if six times its complement is 12° less than it's supplement , we have\r
\n" ); document.write( "\n" ); document.write( "\"6%2890-alpha%29%2B12=180-alpha\"\r
\n" ); document.write( "\n" ); document.write( "\"540-6alpha%2B12=180-alpha\"\r
\n" ); document.write( "\n" ); document.write( "\"540-180%2B12=6alpha-alpha\"\r
\n" ); document.write( "\n" ); document.write( "\"372=5alpha\"\r
\n" ); document.write( "\n" ); document.write( "\"372%2F5=alpha\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28alpha=74.4%29\"->the measure of your angle\r
\n" ); document.write( "\n" ); document.write( "then
\n" ); document.write( "-> complement of \"74.4\" is \"90-74.4=15.6\"
\n" ); document.write( "->supplement of \"74.4\" is \"180-74.4=105.6\"\r
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "\"6%2890-alpha%29%2B12=180-alpha\"\r
\n" ); document.write( "\n" ); document.write( "\"6%2815.6%29%2B12=105.6\"\r
\n" ); document.write( "\n" ); document.write( "\"93.6%2B12=105.6\"\r
\n" ); document.write( "\n" ); document.write( "\"105.6=105.6\"\r
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