document.write( "Question 1084695: if the speed of an aeroplane is reduced by 40km per hr,it takes 20 minutes more to cover 1200km. find the speed of the aeroplane. \n" ); document.write( "
Algebra.Com's Answer #698749 by Boreal(15235)\"\" \"About 
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speed*time=distance
\n" ); document.write( "x is base speed of plane
\n" ); document.write( "x*t=1200
\n" ); document.write( "(x-40)(t+(1/3))=1200
\n" ); document.write( "so xt=xt+(1/3)x-40t-40/3
\n" ); document.write( "0=(1/3)x-40t-40/3; x=1200/t
\n" ); document.write( "0=(400/t)-40t-(40/3)
\n" ); document.write( "multiply by 3t
\n" ); document.write( "0=1200-120t^2-40t
\n" ); document.write( "120t^2-40t-1200=0
\n" ); document.write( "3t^2-t-30=0
\n" ); document.write( "(3t-10)(t+3)=0
\n" ); document.write( "t=10/3 hours, only positive root.
\n" ); document.write( "x*10/3=1200
\n" ); document.write( "10x=3600
\n" ); document.write( "x=360 km/h, ANSWER, and it will take 3 1/3 hours to go 1200 km
\n" ); document.write( "x-40=320 km/h, and it will take 3 2/3 hours (20 more minutes) to go 1200 km.
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