document.write( "Question 1084616: Find the slope of the line tangent to the curve y^2=12x at (3,6) \n" ); document.write( "
Algebra.Com's Answer #698728 by Fombitz(32388)\"\" \"About 
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Find the value of the derivative at that point, it's the slope of the tangent line.
\n" ); document.write( "Implicitly differentiating,
\n" ); document.write( "\"2ydy=12dx\"
\n" ); document.write( "\"dy%2Fdx=6%2Fy\"
\n" ); document.write( "So at (3,6),
\n" ); document.write( "\"m=dy%2Fdx=6%2F6=1\"
\n" ); document.write( "Using the point slope form of a line,
\n" ); document.write( "\"y-6=1%28x-3%29\"
\n" ); document.write( "\"y-6=x-3\"
\n" ); document.write( "\"y=x%2B3\"
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