document.write( "Question 1084646: Statistics calculated from a sample of 22 observations are: \r
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document.write( "∑ (n=22 and i=1) x = 1451\r
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document.write( "∑ (n=22 and i=1) x^2 = 106639\r
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document.write( "(a) Find the sample mean: I found this to be 1451/22
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document.write( "(b) What is the sample standard deviation?
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document.write( "(c) Assume that the population distribution is normal. Find a 95% confidence interval for the population mean. ( , ) \n" );
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Algebra.Com's Answer #698717 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Part (a) \n" ); document.write( "Correct. The fraction 1451/22 approximates to 65.9545454545454 \n" ); document.write( "------------------------------------------------------- \n" ); document.write( "Part (b) \n" ); document.write( "Notation notes: \n" ); document.write( "When I say \"sigma(X^2)\" I mean \n" ); document.write( "Similarly, \"sigma(X)\" means \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Using those values and n = 22, we can use the formula below to get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "s = sqrt( (n*sigma(X^2)-(sigma(X))^2)/(n*(n-1)) ) \n" ); document.write( "s = sqrt( (22*106639-(1451)^2)/(22*(22-1)) ) \n" ); document.write( "s = sqrt( (22*106639-2105401)/(22*21) ) \n" ); document.write( "s = sqrt( (2346058-2105401)/(462) ) \n" ); document.write( "s = sqrt( (240657)/(462) ) \n" ); document.write( "s = sqrt( 520.902597402597 ) \n" ); document.write( "s = 22.8232906786598\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "which is the approximate answer to part (b) \n" ); document.write( "------------------------------------------------------- \n" ); document.write( "Part (c)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We're given n = 22 as the sample size.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Because n > 30 is not true and we don't know sigma (population standard deviation) we must use the T distribution. \n" ); document.write( "The degrees of freedom (df) are \n" ); document.write( "df = n-1 \n" ); document.write( "df = 22-1 \n" ); document.write( "df = 21\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The value of xbar is approximately 65.9545454545454 as done in part (a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use a table such as this one to locate the df = 21 row. \n" ); document.write( "I have marked this row with a red rectangle (see below) \n" ); document.write( "In this df = 21 row, mark the value that is directly over top the \"95%\" confidence level \n" ); document.write( "I marked this entire column with a blue rectangle (see below) \n" ); document.write( "The red and blue rectangles intersect at the value 2.080 \n" ); document.write( " ![]() \n" ); document.write( "So the t critical value is t = 2.080\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Earlier in part (b) we calculated the sample standard deviation to be approximately s = 22.8232906786598\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We take these values (xbar = 65.9545454545454, t = 2.080, s = 22.8232906786598, n = 22) to plug into the formulas below\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = xbar - t*(s/sqrt(n)) \n" ); document.write( "L = 65.9545454545454 - 2.08*(22.8232906786598/sqrt(22)) \n" ); document.write( "L = 65.9545454545454 - 2.08*(22.8232906786598/4.69041575982343) \n" ); document.write( "L = 65.9545454545454 - 2.08*(4.8659419222826) \n" ); document.write( "L = 65.9545454545454 - 10.1211591983478 \n" ); document.write( "L = 55.8333862561976\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "U = xbar + t*(s/sqrt(n)) \n" ); document.write( "U = 65.9545454545454 + 2.08*(22.8232906786598/sqrt(22)) \n" ); document.write( "U = 65.9545454545454 + 2.08*(22.8232906786598/4.69041575982343) \n" ); document.write( "U = 65.9545454545454 + 2.08*(4.8659419222826) \n" ); document.write( "U = 65.9545454545454 + 10.1211591983478 \n" ); document.write( "U = 76.0757046528932\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The 95% confidence interval for the mean (mu) is (L,U) = (55.8333862561976,76.0757046528932), which is an approximate interval. \n" ); document.write( " \n" ); document.write( " |