document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95929>Question 95929</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If P dollars is invested at 100r percent compounded annually, at the end of 2 years it will grow to A=P(1+r)2<BR>\n" );
document.write( "At what interest rate will $100 grow to $144.00 in 2 yrs If A=144 and P =100 , find r  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69871 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 144=100(1+R)^2<BR>\n" );
document.write( "144=100(1+2R+R^2)<BR>\n" );
document.write( "144=100+200R+100R^2 <BR>\n" );
document.write( "NOW WE PUT THESE TERMS IN THE QUADRATIC FORMULA FORMAT<BR>\n" );
document.write( "100R^2+200R+100-144=0 NOW WE COMBINE THE NUMERIC TERMS<BR>\n" );
document.write( "100R^2+200R-44=0 NOW WE EXTRACT A COMMON FACTOR 4<BR>\n" );
document.write( "4(25R^2+50R-11)=0 NOW WE FACTOR THE EQUATION<BR>\n" );
document.write( "(5X+11)(5X-1)=0 NOW WE SOLVE ONLY THE FACTOR THAT GIVES A POSITIVE ANSWER.<BR>\n" );
document.write( "5X-1=0<BR>\n" );
document.write( "X=1/5<BR>\n" );
document.write( "X=.2 IS THE RATE OF INTEREST OR 20%. </SPAN>\n" );
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