document.write( "Question 1084552: The sum to m term of the series 1 +11+111...... upto m term is equal to: \n" ); document.write( "
Algebra.Com's Answer #698706 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Didn't see how 9*S[n] would help, ideally looking for something that is closer to 10^n for each S[n], so we can find a pattern in the amounts to subtract from 10^n to arrive at S[n]:\r \n" ); document.write( "\n" ); document.write( "— \n" ); document.write( "Note that \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "gives us \n" ); document.write( "and \n" ); document.write( "\n" ); document.write( "—\r \n" ); document.write( "\n" ); document.write( "Spot Check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "—\r \n" ); document.write( "\n" ); document.write( "I found this by trial and error, maybe another tutor has a more structured approach. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |