document.write( "Question 1084617: Find the slope of the line tangent to the curve y^2=12x at (3,6) \n" ); document.write( "

Algebra.Com's Answer #698696 by josmiceli(19441) $\"\"$ $\"About$

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$\"+y%5E2+=+12x+\"$
\n" ); document.write( " $\"+y+=+%28+12x+%29%5E%281%2F2%29+\"$
\n" ); document.write( " $\"+y%5B1%5D+=+%281%2F2%29%2A+%28+12x+%29%5E%28-1%2F2%29%2A12+\"$
\n" ); document.write( " $\"+y%5B1%5D+=+6%2A%28+12x+%29%5E%28-1%2F2%29+\"$
\n" ); document.write( "at (3,6)
\n" ); document.write( " $\"+y%5B1%5D+=+6%2A%28+12%2A3%29%5E%28-1%2F2%29+\"$
\n" ); document.write( " $\"+y%5B1%5D+=+6%2Fsqrt%2836%29+\"$
\n" ); document.write( " $\"+y%5B1%5D+=+6%2F6+\"$
\n" ); document.write( " $\"+y%5B1%5D+=+1+\"$
\n" ); document.write( "--------------------
\n" ); document.write( "Here are plots of $\"+y+\"$ and $\"+y%5B1%5D+\"$
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