document.write( "Question 95912: I'm not sure if this is the right category but here is my problem:\r
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document.write( "Lupe's mother paid $7.40 to buy juice for the 14 members of Lupe's softball team. If a bottle of orange juice costs 55 cents and a bottle of apple juice costs 45 cents, how many of each type did she buy?
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document.write( "I have tried trial and error, and I have gotten the correct answer (3 apple, 11 orange) however, trial and error can take a long time for larger numbers and so I would like to know what the algebraic equation is, preferably using 1 variable. thank you for your time \n" );
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Algebra.Com's Answer #69868 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! X+Y=14 OR X=14-Y \n" ); document.write( "55X+45Y=740 NOW REPLACE X WITH(14-Y) & SOLVE FOR Y \n" ); document.write( "55(14-Y)+45Y=740 \n" ); document.write( "770-55Y+45Y=740 \n" ); document.write( "-10Y=740-770 \n" ); document.write( "-10Y=-30 \n" ); document.write( "Y=-30/-10 \n" ); document.write( "Y=3 AMOUNT OF APPLE JUICE BOUGHT \n" ); document.write( "X=14-3=11 ORANGE JUICE BOUGHT. \n" ); document.write( "PROOF \n" ); document.write( "55*11+45*3=740 \n" ); document.write( "605+135=740 \n" ); document.write( "740=740\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |