document.write( "Question 1084583: Find the slope of the line tangent to the curve y^2=12x at (3,6)
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Algebra.Com's Answer #698673 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 2yy'=12, using implicit differentiation. \n" ); document.write( "yy'=6 \n" ); document.write( "y'=6/y \n" ); document.write( "when y=6, y'=1 \n" ); document.write( "use point slope formula y-y1=m(x-x1), m slope (x1,y1) point \n" ); document.write( "y-6=x-3 \n" ); document.write( "y=x+3; slope is 1 ANSWER \n" ); document.write( " |