document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084545>Question 1084545</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider the functions f(x) = sqrt x-1 and g(x) = ax+b. In the standard (x,y) coordinate plane, y = f(g(x)) passes through (0,1) and (2,3). What is the value of a+b?<BR>\n" );
document.write( "So far I have f(g(x)) = sqrt (ax+b) -1, slope = 2, y-3 = sqrt(2x-5). Now I don't know what to do or if I am even doing it correctly. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698643 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698643\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(g(x)) = square root(ax + b) - 1<BR>\n" );
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document.write( "1)  square root(a*0+b) -1 = 1<BR>\n" );
document.write( "square root(b) = 2<BR>\n" );
document.write( "b = 4<BR>\n" );
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document.write( "2)  square root(a*2+4) -1 = 3<BR>\n" );
document.write( "square root(2a+4) = 4<BR>\n" );
document.write( "2a+4 = 16<BR>\n" );
document.write( "a = 6<BR>\n" );
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document.write( "a+b = 6+4 = 10<BR>\n" );
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