document.write( "Question 1084546: When x does not equal 7, (3x/x^2-49) + (3x/7-x) is equivalent to? \n" ); document.write( "

Algebra.Com's Answer #698637 by Boreal(15235) $\"\"$ $\"About$

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(3x/(x+7)(x-7))+3x/(x-7)=
\n" ); document.write( "This needs to be put over a common denominator, which could be (x^2-49)(7-x), but if we multiply the second term by -1/-1, it become -(instead of +)3x/(x-7)
\n" ); document.write( "Now the expression is
\n" ); document.write( "3x/(x^2-49)-3x/(x-7)
\n" ); document.write( "This can be put over a common denominator of x^2-49, which is (x+7)(x-7)
\n" ); document.write( "Therefore the answer is 3x/(x2-49)-3x(x+7)/(x-7)(x+7)
\n" ); document.write( "This is 1/(x^2-49){3x-3x^2-21x)
\n" ); document.write( "=-3x^2-18x/(x^2-49), or -3x(x+6)/x^2-49)
\n" ); document.write( "x not equal to 7
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