document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084549>Question 1084549</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For a x in the domain of the function (x+2)/(x^3-x), this function is equivalent to:<BR>\n" );
document.write( "F) (1/x^2-1)+(2/x^3-x)   G) (2/x^2-1)   H) (1/x^2-1)   J) (1/x-1)   K) (1/x+1)<BR>\n" );
document.write( "I got G by doing (x+2)/x(x^2-1) and cancelling out the x's, but the actual answer is F. How do I get F? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698624 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698624\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Break out the numerator so that <BR>\n" );
document.write( "(x+2)/(x^3-x)=x/(x^3-x) + 2/(x^3-x)<BR>\n" );
document.write( "The first term of that will become 1/(x^2-1) </SPAN>\n" );
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