document.write( "Question 1084512: There are ten cards labelled 1 to 10. Jacky takes out two cards without replacing them. Find the probability that both show even numbers.\r
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Algebra.Com's Answer #698600 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the cards are numbered 1 to 10.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "there are 5 odd numbers and 5 even numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the odd numbers are 1,3,5,7,9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the even numbers are 2,4,6,8,10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the probability of getting an even number on the first draw is 5/10.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "assuming that an even number was drawn, then the probability of getting an even number on the second draw is 4/9.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is because you drew one of the even numbers from the pot so there are 4 even numbers left and you drew one of ten numbers from the pot so there are 9 numbers left.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "therefore, the probability of getting an even number on both draws is 5/10 * 4/9 = 20/90 = 2/9.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |