document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084502>Question 1084502</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how far would you walk to go around the outside of a room 9'3\" x 12'6\"<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698593 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698593\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "To walk round the outside of a room <BR>\n" );
document.write( "would be walking around the perimeter of the room<BR>\n" );
document.write( "Perimeter = 2 x Length + 2 x breadth.<BR>\n" );
document.write( "I will assume length of room = 12' 6\" and the breadth<BR>\n" );
document.write( "= 9' 3\"<BR>\n" );
document.write( "Perimeter = (2 x 12' 6\") + (2 x 9' 3\")<BR>\n" );
document.write( "Perimeter = (25') + (18' 6\")<BR>\n" );
document.write( "Perimeter = 43' 6\".<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );