document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084495>Question 1084495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Y varies directly as x and inversely as the square of z. y=8 when x=50 and z=5. Find y when x=20 and z=2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698590 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698590\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> direct variation is y = kx\r<BR>\n" );
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document.write( "indirect variation is y = k/x\r<BR>\n" );
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document.write( "direct and indirect combined variation is y = kx/z\r<BR>\n" );
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document.write( "in your problem, z is equal to z^2.\r<BR>\n" );
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document.write( "it's the same formula except you replace z with z^2.\r<BR>\n" );
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document.write( "the direct and indirect combined variation formula becomes y = kx/z^2\r<BR>\n" );
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document.write( "y = 8 when x = 50 and z = 5.\r<BR>\n" );
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document.write( "formula becomes 8 = 50 * k / 5^2\r<BR>\n" );
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document.write( "simplify this to get 8 = 50 * k / 25\r<BR>\n" );
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document.write( "simplify further to get 8 = 2 * k\r<BR>\n" );
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document.write( "divide both sides of this equation by 2 and solve for k to get k = 4\r<BR>\n" );
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document.write( "now that you know the value of k, you can solve the problem.\r<BR>\n" );
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document.write( "the problem is find y when x = 20 and z = 2\r<BR>\n" );
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document.write( "formula of y = kx / z^2 becomes y = 20*4/4 which becomes y = 20\r<BR>\n" );
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document.write( "that's your solution.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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