document.write( "Question 95896: I'm struggling on this one & it's probably easy but I just can't seem to get it, PLEASE HELP...
\n" ); document.write( "Quadratic Eq.
\n" ); document.write( "Jane invested some amount of money at a rate of 12% simple interest and some other amount at the rate of 10% simple interest. She received yearly interest of $130.Randy also invested in the same scheme, but he interchanged amounts invested and received $4 more interest. How much did each of them invest at different rates?
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Algebra.Com's Answer #69859 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
.12X+.10Y=130 MULTIPLY BY -.10 (-.012X-.010Y=-13)
\n" ); document.write( ".10X+.12Y=134 MULTIPLY BY .12 (.012X+.0144Y=16.08)
\n" ); document.write( "NOW ADD:
\n" ); document.write( ".012X+.0144Y=16.08
\n" ); document.write( "-.012X-.010Y=-13
\n" ); document.write( "-----------------------------------------
\n" ); document.write( ".0044Y=3.08
\n" ); document.write( "Y=3.08/.0044
\n" ); document.write( "Y=700 INVESTED BY JANE @ 10%
\n" ); document.write( ".12X+.10*700=130
\n" ); document.write( ".12X+70=130
\n" ); document.write( ".12X=130-70
\n" ); document.write( ".12X=60
\n" ); document.write( "X=60/.12
\n" ); document.write( "X=500 INVESTED BY JANE @ 12%
\n" ); document.write( "PROOF USING RANDY'S INVESTMENTS
\n" ); document.write( ".12*700+.10*500=134
\n" ); document.write( "84+50=134
\n" ); document.write( "134=134
\n" ); document.write( "
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