document.write( "Question 1084428: jim's burgers sell for $1.80 each.
\n" ); document.write( "unit cost is $.95
\n" ); document.write( "weekly fixed cost is $475.00 for restaurant
\n" ); document.write( "how many burgers must be sold per week for a profit to be made?
\n" ); document.write( "

Algebra.Com's Answer #698536 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Profit = Revenue - Cost
\n" ); document.write( "Let \"+n+\" = number of burgers sold in one week
\n" ); document.write( "For a one week period:
\n" ); document.write( "\"+P+=+R+-+C+\"
\n" ); document.write( "\"+R+=+1.8n+\"
\n" ); document.write( "\"+C+=+.95n+%2B+475+\"
\n" ); document.write( "\"+P+=+1.8n+-+%28+.95n+%2B+475+%29+\"
\n" ); document.write( "\"+P+=+1.8n+-+.95n+-+475+\"
\n" ); document.write( "\"+P+=+1.75n+-+475+\"
\n" ); document.write( "The \"break even point\" ( zero profit ) is when:
\n" ); document.write( "\"+P+=+0+\"
\n" ); document.write( "\"+1.75n+-+475+=+0+\"
\n" ); document.write( "\"+1.75n+=+475+\"
\n" ); document.write( "\"+n+=+271.43+\"
\n" ); document.write( "That means 272 burgers must be sold before
\n" ); document.write( "there is a profit
\n" ); document.write( "--------------------
\n" ); document.write( "check:
\n" ); document.write( "\"+P+=+1.75n+-+475+\"
\n" ); document.write( "\"+n+=+272+\"
\n" ); document.write( "\"+P+=+1.75%2A272+-+475+\"
\n" ); document.write( "\"+P+=+476+-+475+\"
\n" ); document.write( "\"+P+=+1+\"
\n" ); document.write( "Looks OK
\n" ); document.write( "
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