document.write( "Question 1084423: m/2+n/2=13/10
\n" ); document.write( "3(m-n)=m-10 \n" ); document.write( "

Algebra.Com's Answer #698524 by ikleyn(52786) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( " = ,        (1)\r\n" );
document.write( "3(m-n) = m-10.    (2)\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Multiply equation (1) by 60 (both sides).  You will get an equivalent equation\r\n" );
document.write( "\r\n" );
document.write( "30m + 30n = 78.       (1')\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Simplify equation (2) step by step. You will get equivalent equations\r\n" );
document.write( "\r\n" );
document.write( "3m - 3n = m - 10,\r\n" );
document.write( "\r\n" );
document.write( "2m - 3n = -10,\r\n" );
document.write( "\r\n" );
document.write( "20m - 30n = -100.     (2')\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Now add equations (1') and (2') (both sides). You will get\r\n" );
document.write( "\r\n" );
document.write( "50 m = 78 - 100 = -22.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Hence, m =  = .\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Now from equation (1)   =  =  =  =  = .\r\n" );
document.write( "\r\n" );
document.write( "Hence,  n =  = .\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Answer.  n = ,  m = .\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );