document.write( "Question 1084401: A roll of paper has an external diameter of 3' and internal diameter of 8\". The paper is .005\" thick. Determine length of paper. \r
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document.write( "Answer given: 16130 ft. \r
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document.write( "My attempt: \r
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document.write( "Volume of hollow cylinder: pi(R + r)(R - r) R = larger radius, r = smaller radius. \r
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document.write( "Let l = length. \r
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document.write( "l * .005 = pi(18 + 4)(18 - 4) \r
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document.write( "l = pi / .005 = pi(18 + 4)(18 - 4) \r
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document.write( "l = pi(18 + 4)(18 - 4) / .005 \r
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document.write( "l = pi(324 - 72 + 72 - 16) / .005 \r
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document.write( "l = pi(308 / .005) \r
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document.write( "l = pi * 61600 \r
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document.write( "l = 193522.96 = 193523 in. = 16126.9166 = 16127 ft. \r
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document.write( "Where am I incorrect? Non-homework.\r
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document.write( "
Algebra.Com's Answer #698502 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A roll of paper has an external diameter of 3' and internal diameter of 8\". The paper is .005\" thick. Determine length of paper. \r \n" ); document.write( "\n" ); document.write( "Answer given: 16130 ft. \n" ); document.write( "=========== \n" ); document.write( "OD - ID = 36 - 8 = 28 inches --> r = 14 inches \n" ); document.write( "14/0.005 = 2800 turns. \n" ); document.write( "----- \n" ); document.write( "Average diameter = (36+8)/2 = 22 inches \n" ); document.write( "--- \n" ); document.write( "22*pi*2800 = 193522 inches \n" ); document.write( "= 16127 feet \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |