document.write( "Question 1084371: QUADRATIC EQUATION
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document.write( "1) THE AREA OF A RECTANGULAR GROUND IS 54SQUARE M. IF THE LENGTH OF THE GROUND IS 2M LESS AND 1M MORE, IT WILL HAVE BEEN A SQUARE. FIND LENGTH AND BREADTH OF THE GROUND \n" );
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Algebra.Com's Answer #698471 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the area of the rectangle is 54 square meters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the length is 2 meters less and the width is 1 meter more, it will have been a square.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "assume the length of the rectangle is x and the width of the rectangle is y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in order for it to be a square, you need to shorten the length by 2 meters and increase the width by 1 meter.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you would get x-2 is the length and y + 1 is the width.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if it is now a square, then x-2 = y+1 because all sides are equal in a square.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can solve for y to get y = x-3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "go back to your rectangle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the area is 54 square meters which is equal to x * y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since y is equal to x-3, you get x * (x-3) = 54\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get x^2 - 3x = 54\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 54 from both sides to get x^2 - 3x - 54 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor to get (x-9) * (x+6) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get x = 9 or x = -6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x can't be negative so x has to be 9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since x * y = 54, when x = 9, y has to be equal to 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get x * y = 9 * 6 = 54\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it's a rectangle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you subtract 2 from the length and add 1 to the width, you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(9-2) * (6+1) = 7 * 7 = 49\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it's now a square with each side equal to 7 and the area of the square is 49 square meters.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |