document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95871>Question 95871</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Carl and Fred started driving from the same point, Carl driving due east and Fred traveling due west.  The rate at which Carl drove was twice that of Fred.  After four hours, they were 600 miles apart.  Find the rate of each. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69844 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (f+2f)4=600<BR>\n" );
document.write( "3f*4=600<BR>\n" );
document.write( "12f=600<BR>\n" );
document.write( "f=600/12<BR>\n" );
document.write( "f=50 mph for Fred's speed.<BR>\n" );
document.write( "c*2*50=100 mph for Carl.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "(50+100)4=600<BR>\n" );
document.write( "150*4=600<BR>\n" );
document.write( "600=600 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );