document.write( "Question 95870: Mary is presently twice as old as Maggy. Ten years ago, Maggy's age was one-third of Mary's then. Ten years from now, Maggy's age will be three-fifths of Mary's age then. How old is each? \n" ); document.write( "
Algebra.Com's Answer #69842 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Mary is presently twice as old as Maggy. Ten years ago, Maggy's age was one-third of Mary's then. Ten years from now, Maggy's age will be three-fifths of Mary's age then. How old is each? \n" ); document.write( "--------------------- \n" ); document.write( "NOW DATA: \n" ); document.write( "Let Maggy's age be x yrs old; Mary's age is 2x yrs old \n" ); document.write( "-------------------------------- \n" ); document.write( "Ten Yrs Ago DATA: \n" ); document.write( "Maggy's age then = x-10 yrs old; Mary's age then 2x-10 yrs old \n" ); document.write( "--------------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "x-10 = (1/3)(2x-10) \n" ); document.write( "x-10 = (2/3)x-(1/10) \n" ); document.write( "(1/3)x = 9.9 \n" ); document.write( "x = 29.7 yrs old (Maggy's age NOW) \n" ); document.write( "2x = 59.4 yrs old (Mary's age NOW) \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |