document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95813>Question 95813</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please Help, how do you graph  <BR>\n" );
document.write( "y = -3/4x + 3  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69841 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69841\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y=-3/4X+3 THIS LINE HAS A SLOPE OF -3/4 & A Y INTERCEPT OF (0,3)<BR>\n" );
document.write( "TO FIND A SECOND POINT SET Y=0 & SOLVE FOR X THUS;<BR>\n" );
document.write( "0=-3X/4+3<BR>\n" );
document.write( "3X/4=3 NOW CROSS MULTIPLY:<BR>\n" );
document.write( "3X=3*4<BR>\n" );
document.write( "3X=12<BR>\n" );
document.write( "X=12/3<BR>\n" );
document.write( "X=4 OR (4,0) FOR THE SECOND POINT.<BR>\n" );
document.write( "NOW PLOT THESE 2 POINTS & DRAW THE LINE THUS:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-3x%2F4+%2B3%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-3x%2F4+%2B3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -3x/4 +3).  </SPAN>\n" );
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