document.write( "Question 1084311: I am preparing my self for the upcoming next level algebra semester in the fall. I have a practice test with some problems I will encounter during the semester. As a reference I am using Blitzer (great book) along with the solution manual. Right of the rip I was hit with this problem, which I can not find in the book. Please tell the name of this problem so I can look it up in the book and find other similar problems to practice and show me the steps involved to solve the problem and I will figure it out. its two square roots multiplied against each other. ∛(□((x^0 y^4)/(3z^3 ))) . ∛(81x^9 y^(-10) z^6 )Simplify completely.
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Algebra.Com's Answer #698409 by Boreal(15235) $\"\"$ $\"About$

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The cube root of (y^4/z^3) (x^0=1) is (y/z)*y^(1/3)
\n" ); document.write( "The cube root of the second is 4x^3*z^2/y^3*y^(1/3)
\n" ); document.write( "The y^1/3 cancel and the answer is 4x^3*z/y^2
\n" ); document.write( "taking the cube root raises the exponent present to the (1/3) power.
\n" ); document.write( "This is multiplying square roots or in this case cube roots.
\n" ); document.write( "If they have the same index, they can be multiplied together directly. If the index is different, it can be converted to a fractional exponent. sqrt (x)* cube rt (x)=x^(1/2)*x^(1/3)=x^(5/6) \n" ); document.write( "

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