document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1084304>Question 1084304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sum of two numbers is 97 and their difference is 37, their product is<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #698402 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52778)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=698402\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "The condition says\r<BR>\n" );
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document.write( "x + y = 97,<BR>\n" );
document.write( "x - y = 37.\r<BR>\n" );
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document.write( "Add the two equation (both sides). \r<BR>\n" );
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document.write( "In this way find x. \r<BR>\n" );
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document.write( "Having x found, find y from either equation.\r<BR>\n" );
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document.write( "Then calculate the product x*y.\r<BR>\n" );
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