document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95817>Question 95817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An automatic coin counter at a bank indicates that $65 in dimes and quarters was processed.  If there were 389 coins how many of each were there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69836 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69836\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D+Q=389 OR D=389-Q<BR>\n" );
document.write( "10(389-Q)+25Q=6500<BR>\n" );
document.write( "3890-10Q+25Q=6500<BR>\n" );
document.write( "15Q=6500-3890<BR>\n" );
document.write( "15Q=2610<BR>\n" );
document.write( "Q=2610/15<BR>\n" );
document.write( "Q=174 QUARTERS<BR>\n" );
document.write( "389-174=215 DIMES.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "10*215+25*174=6500<BR>\n" );
document.write( "2150+4350=6500<BR>\n" );
document.write( "6500=6500 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );